The following routine will read an ArrayList of Byte[] and load each entry into the zip file.
\r\nWhen I use zip.save(somefilename) it saves my zip file to my disk and looks perfect.
\r\nBut, now I need to return a byte[] from this method which contains the zip file.
How would I do this?
\r\nAny help will be greatly appreciated.
\r\nprivate byte[] GenerateMergedZipFile(ArrayList files, string[] byteInfo, string finalZipFormat, string ZipFileName)
\r\n{
\r\n byte[] result = null;
\r\n
\r\n using (ZipFile zip = new ZipFile())
\r\n {
\r\n int ctr = 0;
\r\n foreach (Byte[] inputFile in files)
\r\n {
\r\n // Add the stream into the zip entry.
\r\n ZipEntry e = zip.AddEntry(byteInfo[ctr] + "." + finalZipFormat, inputFile);
\r\n ctr++;
\r\n }
\r\n // Save the zip file.
zip.Save ???
\r\n result =??
\r\n return result;
\r\n }
\r\n}
If what you want is an array of bytes containing the data for the zipfile, I suggest passing a MemoryStream to your call to ZipFile.Save(), and then calling the ToArray() method on the MemoryStream. There's no need to save the zipfile to a filesystem file.
\r\nIf you want BOTH a filesystem file and a byte array, then save to a filesystem file, and then read the data from the filesystem file using the appropriate method on the System.IO.File class. Or, you could do the converse - save to a MemoryStream, then write the data into the filesystem file using the appropriate method on the System.IO.File class.
\r\nGood luck.
\r\n", "PostedDate": "2011-03-09T06:10:14.693-08:00", "UserRole": null, "MarkedAsAnswerDate": null }, { "Id": "577723", "ThreadId": "248017", "Html": "\r\n
Thanks for your response.
\r\n\r\n
\r\n
\r\n
From: Cheeso [email removed]\r\n
\r\nSent: Wednesday, March 09, 2011 9:10 AM
\r\nTo: Chernick, Howie
\r\nSubject: Re: Returning a zip file as a Byte[] in C# ?? [DotNetZip:248017]
From: Cheeso
\r\nIf what you want is an array of bytes containing the data for the zipfile, I suggest passing a MemoryStream to your call to ZipFile.Save(), and then calling the ToArray() method on the MemoryStream. There's no\r\n need to save the zipfile to a filesystem file.
\r\nIf you want BOTH a filesystem file and a byte array, then save to a filesystem file, and then read the data from the filesystem file using the appropriate method on the System.IO.File class. Or, you could do the\r\n converse - save to a MemoryStream, then write the data into the filesystem file using the appropriate method on the System.IO.File class.\r\n
\r\nGood luck.
\r\n\r\n
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