[ { "Id": "187997", "ThreadId": "55666", "Html": "

I have seen the examples on how to compress memorysteam (string variable) items into a zipfile and was able to successfully do this.

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I now want to decompress them back into the memorystream (string variables) from the zip file. Is this possible? Can someone show me an example of how to do this please. I couldn't find any information regarding this.

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Thanks

", "PostedDate": "2009-05-07T23:46:10.83-07:00", "UserRole": null, "MarkedAsAnswerDate": null }, { "Id": "188120", "ThreadId": "55666", "Html": "

I was able to decompress the files into memory like so:

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1      MemoryStream ms = new MemoryStream();
2      using (ZipFile zip = ZipFile.Read(ZipFileToRead))
3      {
4        zip["DataFile.csv"].Extract(ms);
5      }
6    

but I want to tweak my question a little bit.

Say I have a folder in the zip file containing many different files (unknown number), how can I decompress the file into a List<> of say string with each index having each different zip file?
", "PostedDate": "2009-05-08T06:44:57.253-07:00", "UserRole": null, "MarkedAsAnswerDate": null }, { "Id": "188122", "ThreadId": "55666", "Html": "

I think you are mixing things.

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There are a couple of related methods.  One is ZipFile.AddFileFromString() and the other, AddFileFromStream().  They are two distinct methods.  If you want to create an entry in a zip file, using the contents of a string, then use the former.  If you want to use the contents of a stream (including a MemoryStream), use the latter.   In each case the result is a zipfile with an entry.

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I think you are asking about extracting an entry to a stream, or perhaps to a string.  In the extraction case, there is no ExtractToString() method, so you must extract to a stream, using the ZipEntry.Extract(Stream) method, and a MemoryStream.  Example: 

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            using (ZipFile zip = ZipFile.Read(_zipFileName))\r\n            {\r\n                var r = zip["files/Readme.txt"];\r\n                if (r!= null)\r\n                {\r\n                    using (var ms = new MemoryStream())\r\n                    {\r\n                        r.Extract(ms);\r\n\r\n                        byte[] block = ms.ToArray();\r\n                        string readmeString = System.Text.Encoding.Default.GetString(block, 0, block.Length);\r\n                        Console.WriteLine("README: {0}\\n\\nPress <ENTER> to continue...\\n", readmeString);\r\n                        Console.ReadLine();\r\n                    }\r\n                }\r\n            }\r\n
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The code above retrieves an entry by name.  The entry name is "files/Readme.txt" - in other words, in the zip file, there is a Readme.txt file, stored in the "files" directory.  That entry is extracted to a MemoryStream, which is then decoded into a string.  The text encoding used here, for extraction, is System.Text.Encoding.Default.  But you can use any encoding, just ensure that you use the same encoding for extraction that was used for storage.  [FYI: When you use AddFileFromString, DotNetZip encodes the string using the Default encoding]

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", "PostedDate": "2009-05-08T06:45:46.51-07:00", "UserRole": null, "MarkedAsAnswerDate": null }, { "Id": "188127", "ThreadId": "55666", "Html": "

our replies crossed.

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To answer your 2nd Q, something like this might work:

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            var list = new System.Collections.Generic.List<String>();\r\n            using (ZipFile zip = ZipFile.Read(_zipFileName))\r\n            {\r\n                foreach (ZipEntry e in zip.Entries)\r\n                {\r\n                    using (var ms = new MemoryStream())\r\n                    {\r\n                        e.Extract(ms);\r\n\r\n                        byte[] block = ms.ToArray();\r\n                        string contentString = System.Text.Encoding.Default.GetString(block, 0, block.Length);\r\n                        list.Add(contentString);\r\n                    }\r\n                }\r\n            }\r\n
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But that assumes that all files were encoded with the default text encoding, which may or may not be a valid assumption. If there is a file in the zip, for example, that was UTF-8 encoded, then the string resulting from decoding it with the default encoding will not have the desired content.

", "PostedDate": "2009-05-08T06:53:52.14-07:00", "UserRole": null, "MarkedAsAnswerDate": null }, { "Id": "188128", "ThreadId": "55666", "Html": "

HI Cheeso, I think you replied just while I was replying as well. I was able to do something very similar to what you suggested and get a single file out of the zipfile into memorystream and then convert that to a string

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Where im stuck now is decompressing an unknown number of files in a folder within the zip file back into some form (either memorystream or something else) so that I can manipulate and retrieve them.

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Thoughts?

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Thanks

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", "PostedDate": "2009-05-08T06:55:01.72-07:00", "UserRole": null, "MarkedAsAnswerDate": null }, { "Id": "188129", "ThreadId": "55666", "Html": "

Once again our replies crossed over. I will try your second example out.

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Thanks

", "PostedDate": "2009-05-08T06:56:17.113-07:00", "UserRole": null, "MarkedAsAnswerDate": null } ]